"We are two simplified fractions. Our LCD is 12. Our denominators are consecutive integers. The numerator and denominator of one of us has a difference of 3. The other fraction is greater than 50%. Who are we?"
Now it's your turn to make the riddle. Begin yours with "We are two simplified fractions. Our LCD is..." Then continue to give clues that will lead the reader to discover your two simplified fractions.
Be creative with your clues! Make sure that only two fractions are possible answers, and remember, no improper fractions for this activity. Good luck!
We are two simplified fractions. Our LCD is 24. One of us have denominator same as LCD. If we multiply each denominator, it comes out as 288. One of us, which has denominator same as LCD, has difference of 17 between numerator and denominator. The other number has difference of 7 between numerator and denominator. Who are we?
ReplyDeleteLCD Riddle- Liz Lee
ReplyDeleteWe are two simplified fractions. Our LCD 48. The denominators have a difference of 13. One of the numerators is 2/3 of the denominator. The other numerator is one more than half of its denominator.
We are two simplified fractions. Our LCD is 18. When you divide the LCD by 3, it is equal to one of the denominator. Both denominators are even and the numerators are consecutive integers. (I am still missing the Numerators)
ReplyDeleteWe are two simplified fractions. Our LCD is 15. One of the denominators have a prime factorization of 3*5. The other denominator is one of the factors of our LCD. There should be no improper fractions, and the numerator of that fraction is a composite number. Our two numerators are 1 digit apart. Who are we?
ReplyDeleteWe are two simplified fractions. Our LCD is 24. The denominator is consecutive integer. The numerators are 2 difference then the denominator and the numerator have a difference of 4. Who are we?
ReplyDeleteWe are two simplified fractions. Our LCD is the LCM of 3 and 7 times 4. The numerators are two consecutive integers. One of the denominators times 2 minus 2 is the other denominator. The smaller denominator plus the other fraction’s numerator is the bigger denominator. The fraction with the smaller denominator has a numerator that is the GCF of 32 and 20.
ReplyDeleteOur LCD is 960. We are two simplified fractions. Our Denominator of the first fraction multiplied by 5 is our LCD. Our numerators are both prime. Our numerators add up to 230. The numerator of the first fraction is 2x2x2x2x2x2+3. The product of the numerator and the denominator of the second fraction is 52,160. What are we?
ReplyDeleteWe are two simplified fractions. Our LCD is equal to 8x9. Their numerators are both odd and the smaller one is equal to 1. The smaller fraction's denominator is equal to 4 while the other denominator is equal to (2x2x2x2)+2. When their denominators are both equal, the numerator of the greater number is equal to 20.Who are we?
ReplyDeleteMy fractions are simplified. The numerator is a consecutive odd integer. Also my denominator is a consecutive odd integer. The sum of my numerator is 2times the sum of my denominator. What Am I?
ReplyDeleteWe are two simplified fractions. Our LCD is 24. . If we multiply each denominator, it comes out as 288. One of us has difference of 17 between numerator and denominator. The other number has difference of 7 between numerator and denominator. Who are we?
ReplyDeleteWe are two simplified fractions. Our LCD is 12. The denominator is consecutive integer. The numerators are 2 difference then the denominator and the numerator have a difference of 4. Who are we?
ReplyDeleteWe are two simplified fractions. Our LCD is equal to 3x12. The smaller fraction's denominator is equal to 4 while the other denominator is equal to (2x2x2x2)+2. Their numerators are both odd and the smaller one is equal to (4x4x4)÷64+2+3. Who am I?
ReplyDeleteMy fractions are simplified. Our LCD is 63. The numerator is a consecutive odd integer. Also my denominator is a consecutive odd integer. The sum of my numerator is 2times the sum of my denominator. What Am I?
ReplyDeleteWe are two simplified fractions. Our LCD is equal to 3x12. The smaller fraction's denominator is equal to 4 while the other denominator is equal to (2x2x2x2)+2. Their numerators are both odd and the bigger one is equal to (4x4x4)÷64+1+3 while the smaller one is equal to 1. Who am I?
ReplyDeleteWe are two simplified fractions. Our LCD is 12. The denominator is consecutive integer. The numerators have a 2 difference.
ReplyDeleteWe are two simplified fractions. Our LCD is 15. One of the denominators have a prime factorization of 3*5. The other denominator is one of the factors of our LCD. The denominator of the second fraction is larger than the answer to 29*8/58. There should be no improper fractions, and the numerator of both fraction is a prime number. Adding the two numerator would equal the smaller denominator. The two numerators are 1 digit apart. Who are we?
ReplyDeleteMy fractions are simplified. Our LCD is 63. The numerator is a consecutive odd integer. Also my denominator is a consecutive odd integer. The sum of my denominator is 2 times the sum of my numerator. What Am I?
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ReplyDeleteWe are two simplified fractions. Our LCD is 10. The first fraction has a denominator that is the half of the second fraction’s denominator. The second fraction is equivalent to 3 over 30. To find the numerator of the first fraction, you have to solve this equation 4=2x+2
ReplyDelete